11m^2=34m+40

Solution for 11m^2=34m+40 equation:

11m^2=34m+40

We move all terms to the left:

11m^2-(34m+40)=0

We get rid of parentheses

11m^2-34m-40=0

a = 11; b = -34; c = -40;
Δ = b2-4ac
Δ = -342-4·11·(-40)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-54}{2*11}=\frac{-20}{22}
=-10/11
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+54}{2*11}=\frac{88}{22}
=4
$